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    • Q1 Uniform Acceleration >
      • Worked Solutions Ch 1 + 2
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      • Worked Solutions Ch 4
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      • Worked Solutions Ch 3 + 10
      • Written Solutions to Past Papers
    • Q4 Connected Particles >
      • Worked Solutions Ch 5
    • Q5 Collisions >
      • Worked Solutions Ch 6 + 7
    • Q9 Hydrostatics >
      • Worked Solutions Ch 9
    • Q10 Differential Equations >
      • Worked Solutions Ch 12
    • Mistakes!!
  • Past Papers
    • Marking Schemes
    • Mock Papers
    • Other Worked Solutions >
      • Connected Particles
  • Additional Questions
    • Q6 Circular Motion / SHM >
      • Worked Solutions Ch 11 and 13
    • Q7 Statics >
      • Worked Solutions Ch 8
    • Q8 Moments of Inertia >
      • Worked Solutions Ch 14

Uniform linear acceleration

Introduction

This topic is about particles which move in a straight line and accelerate uniformly.  Problems can vary enormously, so you have to have your wits about you.  Problems can be broken down into three main categories:

  • Constant uniform acceleration
  • Time-speed graphs
  • Problems involving two particles

Constant uniform acceleration

Remember what the following variables represent:  t = the time ;  a = the acceleration ; u = the initial speed ; v = the final speed ; s = the displacement from where the particle started.  When the acceleration is negative, it is sometimes called a deceleration or retardation.  For example, an acceleration of  –3 ms-2 is the same as a deceleration (or retardation) of  3 ms-2.

• To answer this question, you will need to use the four key formulae intelligently. 
Picture
• It is important to know the second of these equations off by heart; the others appear on Page 40 of The Mathematical Tables.  Secondly, you may be asked to derive either of the last two equations from the first two.  Practise this.

• These four formulae will be useful elsewhere (for example when doing Questions 3 and 4 on projectiles and connected particles).


Time-speed graphs

Remember that the above formulae may be used only while the acceleration is uniform.  If a particle speeds up, but then travels at a constant speed, and then slows down, the above formulae cannot be used for the entire journey.  In these cases we solve the problem by drawing a time-speed graph, with time as the horizontal axis.

There are four key points to remember about time-speed graphs:

• The area between the graph and the time-axis represents the distance travelled.
Picture
• The slope of the graph represents the acceleration.

• If a particle starts from rest, then v = at  [i.e. the final speed will be the product of the acceleration and the time.]
Picture
• If a particle accelerates from rest for time t1 with acceleration a and immediately decelerates to rest in time t2 with deceleration d, then t1:t2 = d:a
Picture
For example, if the acceleration is 6 ms-2 and the deceleration is 8 ms-2, then  t1:t2 = d:a = 8:6 = 4:3 .  It follows that  of the time will be spent accelerating and  of the time will be spent decelerating. 


Problems involving two particles

• If particles P and Q set off together and later overtake each other, then overtaking will occur when Sp = Sq  .  If, however, P was 25 metres behind Q at the start, then when overtaking occurs, 
Sp = Sq + 25 

• If P and Q are a distance l apart and move towards each other, they will meet when  Sp + Sq = l

• The greatest gap between particles P and Q occurs when vp = vq  (because if their speeds are unequal then the gap is either increasing or decreasing)

• If  particle A sets out and, two seconds later, particle B sets out in pursuit,  then let t = the time which A spends on the road and  t - 2 = the time which B spends on the road.  (Students will often putt + 2 instead of  t - 2.)


Common mistakes

Common mistakes made in doing this question are:

• Assuming that the particle starts from rest, even though this is not stated in the question.

• Using the formulae where they do not apply.

• Jumping into the question before giving it enough clear thought.

• Not drawing a clear time-speed graph.

• Letting u represent the speed at two different moments.  For example, if a particle travels from a to b, a distance of 30 m in 4 seconds and then travels from b to c, a distance of 54 m in a further 3 seconds - how would you find the acceleration?  You let u  = the speed of the particle at a (not anywhere else!).  Then you form an equation for the journey [ab] and another for the journey [ac] .  These equations will be (using s = ut +½at2) : 30 = u(4) +½a(16) and 84 = u(7)+½a(49) .  You solve these simultaneous equations to find a.  NB: You do not form an equation for [bc], as the initial speed will not be the same u as in the first equation.

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